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March 28, 2017

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a simple pendulum has a period of 4.2sec. when the pendulum is shortened by 1 m the period is 3.7s. what is the acceleration of free fall g and the original length of the pendulum?

  • physics - ,

    T = 2 pi sqrt(L/g)

    4.2/(2 pi) = sqrt (L/g)

    3.7/(2 pi) = sqrt ( (L-1)/g )

    L/g = .447
    (L-1)/g = .347 = .447-1/g

    1/g = 0.1

    g = 10
    L = 4.47

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