Homework Help: physics

Posted by la roux on Thursday, April 22, 2010 at 1:06am.

a simple pendulum has a period of 4.2sec. when the pendulum is shortened by 1 m the period is 3.7s. what is the acceleration of free fall g and the original length of the pendulum?

physics - Damon, Thursday, April 22, 2010 at 7:56am
T = 2 pi sqrt(L/g)

4.2/(2 pi) = sqrt (L/g)

3.7/(2 pi) = sqrt ( (L-1)/g )

L/g = .447
(L-1)/g = .347 = .447-1/g

1/g = 0.1

g = 10
L = 4.47

Answer this Question

Related Questions

physics - The period of a simple pendulum is measured to be 4.0 seconds in a ...
physics - The period of a simple pendulum is measured to be 4.0 seconds in a ...
physics - The period of a simple pendulum is measured to be 4.0 seconds in a ...
physics - A pendulum is constructed from a thin, rigid, and uniform rod with a ...
Physics - I got part a but I'm having trouble figuring out b... I know the ...
physics - A simple pendulum consists of a ball connected to one end of a thin ...
Physics - A simple pendulum suspended in a rocket ship has a period To. Assume ...
College Algebra - The period (the time required for one complete swing) of a ...
physics - A pendulum has a length of 1m. What is the period of this pendulum? ...
Physic - The simple pendulum in a tall clock is 0.30 m long. What is the period ...

For Further Reading

First Name:
School Subject:
Answer: