The question asked... Calculate the solubility of calcium sulfate in grams solute per 100 grams solvent. Assume that the volume occupied by the solute in the solution in negligibly small. I solved and got 4.9 x 10 ^-3 mol/L... how do I put this in grams solute per 100 grams solvent?

M = moles/L.

moles = g/molar mass. You know molar mass and you know moles, solve for grams. That, of course, will be grams/L and you take 1/10 of that to obtain g/100 mL of solution which is g/100 mL solvent IF the mass solute is very small.

I came up with 6.67 x 10^-3 g solute/ 100g solvent. Based on the information in the problem, does this seem about right?

I don't know what you used for Ksp; however, based on your answer of 4.9 x 10^-3 moles/L, I think it should be more like 0.0667.

0.0049 x 136 something = 0.666 g/L and 1/10 that is 0.0667.

To convert the solubility of calcium sulfate from moles per liter (mol/L) to grams solute per 100 grams solvent, you need to use the molar mass of calcium sulfate.

The molar mass of calcium sulfate (CaSO₄) is calculated as follows:
Ca: 40.08 g/mol
S: 32.07 g/mol
O₄ (four oxygens): 4 × 16.00 g/mol = 64.00 g/mol
Total molar mass = 40.08 + 32.07 + 64.00 = 136.15 g/mol

Given that the solubility of calcium sulfate is 4.9 × 10⁻³ mol/L, you can now convert this to grams solute per 100 grams solvent.

Step 1: Convert the concentration from mol/L to g/L
To convert the concentration from mol/L to g/L, multiply the concentration (4.9 × 10⁻³ mol/L) by the molar mass of calcium sulfate (136.15 g/mol).
(4.9 × 10⁻³ mol/L) × (136.15 g/mol) = 0.667 g/L

Step 2: Convert g/L to grams solute per 100 grams solvent
To convert grams per liter (g/L) to grams solute per 100 grams solvent, you need to set up the following proportion:
0.667 g/L = x g solute / 100 g solvent

Cross-multiply and solve for x:
0.667 × 100 = x
x = 66.7

Therefore, the solubility of calcium sulfate is approximately 66.7 grams solute per 100 grams solvent.