Posted by Thara! on Wednesday, April 21, 2010 at 8:57pm.
Sn = D[(1+i)^n-1)/i where
Sn = the accumulated sum over n interest periods
D = the periodic deposit
i = the periodic interest paid = I%/100n
n = the number of interest bearing periods
The total interest beariing period is 15 + 12 months
The monthly interest is 6/100(12) = .005
The monthly deposit is $300
Therefore,
S(27)=300[(1.005)^27-1]/.005= $8,649.11
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