Saturday

November 22, 2014

November 22, 2014

Posted by **alexandra** on Wednesday, April 21, 2010 at 2:49pm.

(a) What is the force constant of the spring?

(b) If the 2.60-kg object is removed, how far will the spring stretch if a 1.30-kg block is hung on it?

(c) How much work must an external agent do to stretch the same spring 8.40 cm from its unstretched position?

- physics -
**Damon**, Wednesday, April 21, 2010 at 3:02pm2.30 cm = .0230 meters

2.60 kg * 9.8 m/s^2 = 25.5 Newtons

so

k = 25.5/.0230 = 1108 N/m

1.30*9.8 = 1108 x

x = .0115 m (half as far of course)

Energy stored = work done = (1/2) k x^2

= .5*1108*(.0840)^2

**Answer this Question**

**Related Questions**

physics - When a 2.50-kg object is hung vertically on a certain light spring ...

Physics - When a 2.00-kg object is hung vertically on a certain light spring ...

Physics - When a 3.00-kg object is hung vertically on a certain light spring ...

physics - when a 2.50 kg object is hung vertically on a certain light spring ...

physics - When a 4.48 kg mass is hung vertically on a certain light spring that ...

physic - Hooke's law describes a certain light spring of unstretched length 30.0...

physics - 1)An elastic material has a length of 36cm when a load of 40N is hung ...

PHYSICS!!! - Hooke's law describes a certain light spring of unstressed length ...

Physics - How do you determine the force constant of a spring when given the ...

physics - Sir Robert Hooke (1635-1703), studied the elastic properties of ...