Posted by Scoob on .
An ice cube at 0 degrees Celsius was dropped into 30.0 g of water in a cup at 45.0 degrees Celsius. At the instant that all of the ice was melted, the temperature of the water i the cup was 19.5 degrees Celsius. What was the mass of the ice cube?
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How much heat did the water lose?
mass water x specific heat water x (Tfinal-Tinitial).
How much heat did the ice gain?
mass ice x heat fusion.
The sum of those should be zero.
just use heat gain by ice =heat lost by water.