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Posted by on Tuesday, April 20, 2010 at 9:05pm.

How do you find the derivative of:

ln(3x^2 + x - 1)

I know the derivative of lnx is 1/x

  • calc - , Tuesday, April 20, 2010 at 9:12pm

    If y = ln(junk)
    then dy/dx = junk'/junk

    so y' = (6x+1)/(3x^2 + x - 1)

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