Posted by Ted on Tuesday, April 20, 2010 at 9:05pm.
How do you find the derivative of:
ln(3x^2 + x  1)
I know the derivative of lnx is 1/x

calc  Reiny, Tuesday, April 20, 2010 at 9:12pm
If y = ln(junk)
then dy/dx = junk'/junk
so y' = (6x+1)/(3x^2 + x  1)