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September 30, 2014

September 30, 2014

Posted by **Ted** on Tuesday, April 20, 2010 at 9:05pm.

ln(3x^2 + x - 1)

I know the derivative of lnx is 1/x

- calc -
**Reiny**, Tuesday, April 20, 2010 at 9:12pmIf y = ln(junk)

then dy/dx = junk'/junk

so y' = (6x+1)/(3x^2 + x - 1)

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