Posted by Aliza on Tuesday, April 20, 2010 at 8:20pm.
finally, a name
http://www.jiskha.com/display.cgi?id=1271798615
Y=e^ -√x + e^3 - 2^(3x-1)
Y=e^ -x^(1/2) + e^3 - 2^(3x-1)
Y' = e^ -x^(1/2)(-1/2)x^(-1/2) + 0 - ln2(2^(3x+1))(3)
y = e^-(x^.5) + e^3 -2^(3x-1)
.5x^(-.5) e^-(x^.5) + 0 - 3[2^(3x-1)]*ln2
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