College Chemistry
posted by L** on .
Calculate the electrode potential of a copper halfcall containing 0.05M Cu(NO3).
E^0 Cu2+/Cu = 0.337 V
College Chemistry  DrBob222, Tuesday, April 20, 2010 at 5:19pm
E = Eo  (0.0592/n)log[(Cu)/(Cu^+2)]
Substitute 2 for n and 0.05 M for Cu^+2 and 0.337 for Eo. Solve.
Am I solving for Cu or do I plug a value in for that also?

As I stated in my response, substitute 2 for n and 0.05 M for Cu^+2. You substitute 1 for Cu metal (that is its standard state) and solve for E. E is the only unknown you have.

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