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April 19, 2014

Homework Help: College Chemistry

Posted by L** on Tuesday, April 20, 2010 at 6:18pm.

Calculate the electrode potential of a copper half-call containing 0.05M Cu(NO3).

E^0 Cu2+/Cu = 0.337 V



College Chemistry - DrBob222, Tuesday, April 20, 2010 at 5:19pm
E = Eo - (0.0592/n)log[(Cu)/(Cu^+2)]
Substitute 2 for n and 0.05 M for Cu^+2 and 0.337 for Eo. Solve.


Am I solving for Cu or do I plug a value in for that also?

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