If you were to spin a spinner that had eight equal parts labled 1-8 three times what is the probability that all three numbers are (3 or greater than five)?
results of (3 or > 5) are 3,6,7,8, namely 4 of them
prob for one of these = 4/8 or 1/2
so what is the prob that will happen 3 times in a row?
To solve this problem, we need to first determine the probability of getting a number that is 3 or greater than 5 on a single spin of the spinner. Then, we can calculate the probability of getting such a number three times in a row by raising the probability to the power of 3.
Step 1: Calculate the probability of getting a number that is 3 or greater than 5 on a single spin.
The spinner has eight equal parts labeled 1-8. Out of these eight numbers, the numbers that are 3 or greater than 5 are 6, 7, and 8. Hence, there are three out of eight favorable outcomes.
So, the probability of getting a number that is 3 or greater than 5 on a single spin is 3/8.
Step 2: Calculate the probability of getting such a number three times in a row.
Since each spin is independent, the probability of getting a number that is 3 or greater than 5 on three consecutive spins is found by multiplying the probabilities of each individual spin.
Therefore, the probability of getting such a number three times in a row is (3/8) * (3/8) * (3/8) = 27/512.
Hence, the probability of getting three numbers that are 3 or greater than 5 when spinning the spinner three times is 27/512.