Posted by **Anonymous** on Tuesday, April 20, 2010 at 4:58pm.

Find the local max/min points for the function y=x^2 * e^x

- calculus -
**Reiny**, Tuesday, April 20, 2010 at 5:05pm
by the product rule

y' = x^2(e^x) + 2x(e^x)

= e^x(x^2 + 2x) = 0 for max/min

e^x = 0 ---> no solution or

x^2 + 2x = 0

x(x+2) = 0

x = 0 or x = -2

if x=0 then y 0

if x = -2 then y = 4(e^2)

so (0,0) and ( -2,4e^2) are max/min points.

I will let you decide which is which.

## Answer This Question

## Related Questions

- Calculus - Find any absolute max/min and local max/min for the function f(x)=x^3...
- calculus - a function has a local maximum at x=-2 and x=6 and a local minimum at...
- calculus - I don't understand how to do this? I don't know the steps on how to ...
- Calulus - Consider the function y = 2x^3-3x^2+9x+5. 1. Find where the function ...
- Calculus - You wont get it - Find the local max and local min and saddle points ...
- Calculus Find max and min and saddle - Find and classify all local min and ...
- Calculus (urgent!!) - Consider the function f(x)=12x^5+60x^4−100x^3+4. For...
- Math - Find the critical points and the interval on which the given function is ...
- CALCULUS - 6. f(x)= 12x^5 + 30x^4 - 160x^3 +4 For this function there are four ...
- Calculus - Find the values for which f(x) = x^10-10x and if 0 (less than or ...

More Related Questions