Thursday
March 23, 2017

Post a New Question

Posted by on Tuesday, April 20, 2010 at 4:00pm.

Calculate the electrode potential of a copper half-call containing 0.05M Cu(NO3).

E^0 Cu2+/Cu = 0.337 V

  • College Chemistry - , Tuesday, April 20, 2010 at 5:19pm

    E = Eo - (0.0592/n)log[(Cu)/(Cu^+2)]
    Substitute 2 for n and 0.05 M for Cu^+2 and 0.337 for Eo. Solve.

  • College Chemistry - , Tuesday, April 20, 2010 at 6:17pm

    Am I solving for Cu or do I plug a value in for that also?

  • College Chemistry - , Tuesday, April 20, 2010 at 7:18pm

    Answered above.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question