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How to calculate enthalpy change of the following reaction? :
S + 2h2o >>> so2 + 2h2

given: s+o2 >>> so2 - enthalpy change = -296.8 kJ

h2 + 1/2o2 >> h20 enthalpy change= -285.8kj

I was trying to solve it myself but i got confused.. i know i have to change the second equation to opposite side, but do i also multiply any of these equations by 2?
Thank you, I appreciate your help!

  • chemistry - ,

    Reverse equation 2 and multiply it by 2.

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