Posted by Dave on .
Need an answer to this Calculus Question. I keep getting this type of question wrong. Thanks.
Differentiate the Function:
y = (3x1)^2(2x^4)^2
y =

Calculus 
bobpursley,
do is as a uv problem
d(uv)=vdu+udv
y'=2(3x1)(3) [2x^4)^2 + 2(2x^4)(4x^3)(3x1)^2
have fun gathering terms.