Posted by **MB** on Monday, April 19, 2010 at 3:21pm.

two trains start from towns 208 miles apart and travel towards each other on parallel tracks. They pass each other 1.6 hours later. If one travels 10 mph faster than the other find the speed of each train?

- math -
**MathMate**, Monday, April 19, 2010 at 6:58pm
Sum of speeds = 208 miles/1.6hr=130 mph

Difference of speeds = 10 mph

Faster train = (sum+difference)/2 mph

Slower train = (sum-difference)/2 mph

Explanation:

let f=faster train, s=slower train

S=sum, D=difference, then

S=f+s

D=f-s

Add:

(S+D)=f+s+f-s=2f

therefore f=(S+D)/2

Simlarly, by subtracting,

S-D = f+s - (f-s) = 2s

therefore s=(S-D)/2

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