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Calculate the molar solubility of barium thiosulfate in 0.0045 M Na2S2O3(aq). (Hint: Check any simplifying assumptions that you make.)

  • Chemistry -

    BaS2O3 ==> Ba^+2 + S2O3^-2

    Ksp = (Ba^+2)(S2O3^-2)

    If you call solubility BaS2O3 = S, then S2O3^-2 = S from BaS2O3 and 0.0045 from Na2S2O3 for a total of S+0.0045M. Substitute into Ksp and solve for S. I assume from the hint that you can not make the assumption that S+0.0045 = 0.0045; i.e., that S is not negligible compared to 0.0045 which probably means a quadratic equation solution.

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