Posted by piper on Monday, April 19, 2010 at 1:27pm.
solve the initial value problems:
1 dq/dz = 2 + sinz, q(0)=5
2dy/dx = (x^2 2)x, y(2)=4
3dy/dx = 4e^5^x + x, y(0)=4
4 dy/dx 3x + 2, y(3)= 2

math  Damon, Monday, April 19, 2010 at 2:31pm
q = 2 z cos z + c
when z = 0, q = 5
5 = 1+c
c = 6
so
q = 2z cos z +6

math  Damon, Monday, April 19, 2010 at 5:35pm
dy/dx = (x^2 2)x, y(2)=4
dy/dx = x^3  2x
y = (1/4)x^4  x^2 + c
4 = (1/4)2^4  2^2 + c
that should get you started
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