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March 25, 2017

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solve the initial value problems:
1- dq/dz = 2 + sinz, q(0)=5

2-dy/dx = (x^2 -2)x, y(2)=4

3-dy/dx = 4e^5^x + x, y(0)=4

4- dy/dx 3x + 2, y(3)= 2

  • math - ,

    q = 2 z -cos z + c
    when z = 0, q = 5
    5 = -1+c
    c = 6
    so
    q = 2z -cos z +6

  • math - ,

    dy/dx = (x^2 -2)x, y(2)=4

    dy/dx = x^3 - 2x

    y = (1/4)x^4 - x^2 + c

    4 = (1/4)2^4 - 2^2 + c

    that should get you started

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