Posted by **piper** on Monday, April 19, 2010 at 1:27pm.

solve the initial value problems:

1- dq/dz = 2 + sinz, q(0)=5

2-dy/dx = (x^2 -2)x, y(2)=4

3-dy/dx = 4e^5^x + x, y(0)=4

4- dy/dx 3x + 2, y(3)= 2

- math -
**Damon**, Monday, April 19, 2010 at 2:31pm
q = 2 z -cos z + c

when z = 0, q = 5

5 = -1+c

c = 6

so

q = 2z -cos z +6

- math -
**Damon**, Monday, April 19, 2010 at 5:35pm
dy/dx = (x^2 -2)x, y(2)=4

dy/dx = x^3 - 2x

y = (1/4)x^4 - x^2 + c

4 = (1/4)2^4 - 2^2 + c

that should get you started

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