Friday

October 31, 2014

October 31, 2014

Posted by **KABELO** on Monday, April 19, 2010 at 6:39am.

- PHYS101 -
**Anonymous**, Saturday, January 15, 2011 at 2:39pmA2 = A1/4, so you know A1v1 = A2v2

A1v1 = A1/4v2, cancel out the A1's

v1 = 1/4 v2

v2^2 = 16v1^2 --- eqn 1

change in pressure = (rho)gh = 3332 N/m^2

3332 = 1/2(rho)(v2^2 - v1^2)

3332 = (1/2)(1000)(v2^2 - v1^2)

v2^2 = 6.664 + v1^2 --- eqn 2

16v1^2 = 6.664 + v1^2

v1 = 0.6665 m/s

.... I hope this is right.

**Answer this Question**

**Related Questions**

PHYS101 - A VENTURI TUBE IS USED TO MEASURE THE WATER SPEED V IN A PIPE BY ...

Physics - A venturi meter is a device for measuring the speed of a fluid within ...

Physics - A venturi meter is a device for measuring the speed of a fluid within ...

physics - A venturi meter is a device for measuring the speed of a fluid within ...

physics - A venturi meter is a device for measuring the speed of a fluid within...

Physics - A venturi meter is a device for measuring the speed of a fluid within ...

Physics - Water flows under pressure from one pipe into a second pipe having ...

physics - A horizontal pipe has a cross sectional area of 40.0 cm^2 at the wider...

College Physics - A horizontal pipe has a cross sectional area of 40.0 cm^2 at ...

physic - Water flows through a 4.0-cm-diameler horizontal pipe ata speed uf 1.3 ...