Hi

What is the netionicequation for NaOBr disolving in watr?
Thanks!

NaOBr, the salt of a strong base (NaOH) and a weak acid (HOBr), ionizes in water as follows:

NaOBr(s) + H2O ==> NaOH + HBr and the net ionic equation is
OBr^- + HOH ==> HOBr + OH^-

thank you

wait, if you have

"NaOBr(s) + H2O ==> NaOH + HBr and the net ionic equation is
OBr^- + HOH ==> HOBr + OH^- "
why doesn't this:
NaOBr(s) + H2O ==> NaOH + HBr
become this:
Na+ + OBr- + H2O ==> Na+ + OH- + H+ + Br-

which would become

OBr- + H2O ==> OH- + H+ + Br-

Is the (immediate) above equation the net ionic equation??

Thank you

It does; however, you asked for the NET ionic equation and not the ionic equation. If you use the ionic equation and cancel the ion common to both sides (the Na^+), the net ionic equation results.

In addition, I see I made a typo in the molecular equation. It is
NaOBr + HOH ==> NaOH + HOBr
Finally, no, what you wrote in the "immediate above" equation is not correct since it is based on the wrong molecular equation (because of my typo, I assume). I hope this rsponse makes sense.

The net ionic equation for NaOBr dissolving in water can be determined by considering the dissociation of the compound into its constituent ions in aqueous solution.

To write the net ionic equation, follow these steps:
1. Write the balanced chemical equation for the dissociation of NaOBr in water. In this case, NaOBr dissociates completely into Na+ and OBr- ions.
NaOBr(aq) → Na+(aq) + OBr-(aq)

2. Identify any spectator ions, which are ions that appear on both sides of the equation and do not participate in the reaction. In this case, the Na+ ion is a spectator ion because it remains unchanged before and after the reaction.

3. Write the net ionic equation by omitting the spectator ions. The net ionic equation represents the actual chemical reaction that takes place.
OBr-(aq) → OBr-(aq)

So, the net ionic equation for NaOBr dissolving in water is simply OBr-(aq) → OBr-(aq).

Please note that this equation only shows the dissociation of NaOBr in water and does not represent a chemical reaction involving other species.