Posted by **Samantha** on Sunday, April 18, 2010 at 7:19pm.

I am solving for linear equations and I'm wondering if I did Step 3 right..

3x-y=8

x-y=8

Step 1

3x-y=8

3x-y+y=8+y

3x=8+y

3x/3=8+y/3

x=(8+y/3)

Step 2

3(8+y/3)-y=8

8+y-y=8

8+2y=8

8+2y-8=8-8

2y=0

2y/2=0/2

y=0

Step 3

x=8+y(0)/3

x=2.6

- Algebra1 -
**Reiny**, Sunday, April 18, 2010 at 9:04pm
What a hard way of doing it.

look at the second equation, it is very easy to solve for x

x = 8+y

now sub that into the first

3(8+y) - y = 8

24 + 3y - y = 8

2y = -16

y = -8

back in x = 8+y

x = 8+(-8) = 0

Your last two lines of step1 are wrong

should have been

3x/3=(8+y)/3

x=(8+y)/3

of course that makes all the statements is Step 2 incorrect.

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