Posted by Samantha on Sunday, April 18, 2010 at 7:19pm.
I am solving for linear equations and I'm wondering if I did Step 3 right..
Algebra1 - Reiny, Sunday, April 18, 2010 at 9:04pm
What a hard way of doing it.
look at the second equation, it is very easy to solve for x
x = 8+y
now sub that into the first
3(8+y) - y = 8
24 + 3y - y = 8
2y = -16
y = -8
back in x = 8+y
x = 8+(-8) = 0
Your last two lines of step1 are wrong
should have been
of course that makes all the statements is Step 2 incorrect.
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