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December 21, 2014

December 21, 2014

Posted by **Navroz** on Sunday, April 18, 2010 at 11:49am.

- math -
**Reiny**, Sunday, April 18, 2010 at 3:27pmThe cables of a suspension bridge do not follow the path of a parabola, but since that is what the question asks for ...

centre is (2,0), one other point is (758,50)

y = a(x-2)^2 + 0 , using the centre

but (758,50) lies on it

50 = a(756)^2

a = 50/574564

y = 25/287282(x-2)^2

The cables of most suspension bridges form a

"catenary" (from the Latin 'catena' for chain)

the general equation is

y = a/2(e^(x/a) + e^(-x/a))

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