Posted by Navroz on Sunday, April 18, 2010 at 11:49am.
The cables of a suspension bridge do not follow the path of a parabola, but since that is what the question asks for ...
centre is (2,0), one other point is (758,50)
y = a(x-2)^2 + 0 , using the centre
but (758,50) lies on it
50 = a(756)^2
a = 50/574564
y = 25/287282(x-2)^2
The cables of most suspension bridges form a
"catenary" (from the Latin 'catena' for chain)
the general equation is
y = a/2(e^(x/a) + e^(-x/a))
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