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January 31, 2015

January 31, 2015

Posted by **Nina** on Saturday, April 17, 2010 at 11:21pm.

- Mathematicas -
**tchrwill**, Sunday, April 18, 2010 at 10:19amHere is a similar version of this popular problem which should give you some clues as to how to approach yous.

In a family of children,

1) each girl has as many bothers as sisters but

2) each boy has 3 times as many sisters as brothers.

How many children are in the family?

Let g = the number of girls

Let b = the number of boys

1--Looking at the girls only, it is clear that each girl has one less as many sisters as there are girls in the first place.

2--Therefore, we can write that each girl has (g - 1) sisters.

3--From statement #1, if each girl has as many brothers as sisters, we can write that (g - 1) = b.

4--Similarly, we know that each boy has (b - 1) brothers and g sisters.

5--From statement #2, if each boy has 3 times as many sisters as brothers, we can write that g = 3(b - 1) = 3b - 3.

6--Substituting (5) into (3) yields 3b - 3 - 1 = b.

7--Then, 2b = 4 making b = 2 and g = 3.

Good luck.

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