Posted by **cynthia** on Saturday, April 17, 2010 at 9:38pm.

Assume that a set of test scores is normally distributed with a mean of 100 and a standard deviation of 20. Use the 68-95-99.7 rule to find the following quantities:

a. Percentage of scores less than 100=50 percent

b. Relative frequency of scores less than 120= 0.34+0.135+0.0235+0.015+0.84

c. Percentage of scores less than 140

d. Percentage of scores less than 80

e. Relative frequency of scores less than 60

f. Percentage of scores greater than 120

## Answer This Question

## Related Questions

- stats - Using the 68-95-99.7 rule: Assume that a set of test scores is normally ...
- statistics - Using the 68-95-99.7 rule: Assume that a set of test scores is ...
- statistics - Using the 68-95-99.7 rule: Assume that a set of test scores is ...
- statistic - Using the 68-95-99.7 rule: Assume that a set of test scores is ...
- statics - Using the 68-95-99.7 rule: Assume that a set of test scores is ...
- statistics - Using the 68-95-99.7rule. Assume that a set of test scores is ...
- statistics - Assume that a set of test scores is normally distributed with a ...
- statistics - Assume that a set of test scores is normally distributed with a ...
- Statistics - Assume that a set of test scores is normally distributed with a ...
- Statistics... I need help - . Assume that a set of test scores is normally ...

More Related Questions