Posted by **Anonymous** on Saturday, April 17, 2010 at 8:54pm.

Solve.

The population of a particular country was 29 million in 1980; in 1989, it was 36 million. The exponential growth function A=29e^kt describes the population of this country t years after 1980. Use the fact that 9 years after 1980 the population increased by 7 million to find k to three decimal places.

- Math -
**Reiny**, Saturday, April 17, 2010 at 9:02pm
36 = 29 e^(9k)

1.24138 = e^(9k)

9k = ln (1.24138)

k = ln (1.24138)/9

= ....

- Math -
**bobpursley**, Saturday, April 17, 2010 at 9:03pm
36M=29M*e^k9

take the ln of each side.

ln(36)=ln29+ 9k

k= (ln(36/29)) /9

- Math -
**Anonymous**, Saturday, April 17, 2010 at 9:09pm
Thank you again! Both of u. much appreciated

## Answer this Question

## Related Questions

- Calculus - The population of a region is growing exponentially. There were 40 ...
- Algebra 2 - A country's population in 1991 was 15 million. In 2001 it was 16 ...
- MATH - A table of the U.S. population in millions indicated in 1960 the ...
- algebra - A country's population in 1995 was 175 million. In 2000 it was 181 ...
- Math - Suppose that a country's population is 64 million and its population ...
- Math - Suppose that a country's population is 64 million and its population ...
- calculus - The population of a country was 8.4 million people in 2000. Three ...
- algebra - In 1990, the population of Africa was 643 million and by 2000 it had ...
- Calc - Year 1940 1950 1960 1970 1980 Rate of change (million people per year) 29...
- algebra - A country's population in 1993 was 171 million estimate the population...

More Related Questions