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September 20, 2014

September 20, 2014

Posted by **Abbey(Please help)** on Saturday, April 17, 2010 at 8:30pm.

(r,Q) = (4, 3pi/2)

I know that you are suppose to use

x=r cos Q and y=sin Q but I do not know how to plug this in.

- Math -
**Damon**, Saturday, April 17, 2010 at 8:48pm3 pi/2 is straight down the y axis

x = 4 cos (3pi/2)

but cos 3pi/2 is 0

so x = 0

sin 3pi/2 = -1

so y = -4

so (0,-4)

- Math -
**Reiny**, Saturday, April 17, 2010 at 8:51pmif (r,Q) = (4, 3pi/2)

then r = 4 and Q = 3π/3

now just substitute ...

x = 4cos 3π/2 and y = 4sin 3π/2

x = 0 and y = 4(-1) = -4

so the point is (0,-4)

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