Posted by Abbey on .
Test for symmetry with respect to Q=pi/2 , the polar axis and the pole.
r = 16 cos3Q
Please explain. I do not know how to do this. Thank You!!

Math 
Damon,
if Q = pi/2 + h
r = 16 cos (3pi/2 +3h)
= 16[ cos 3pi/2 cos 3h  sin 3pi/2 sin h ]
cos 3pi/2 = 0
sin 3pi/2 = 1
so
16 sin h
is it the same for h?
if Q = pi/2  h
r = 16 cos (3 pi/2 3h)
=16[ cos 3pi/2 cos 3h + sin3 pi/2 sin 3h
=16 (sin h)
sin h is not the same as sin h
so no, not symmetric about 3pi/2