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December 25, 2014

December 25, 2014

Posted by **Abbey** on Saturday, April 17, 2010 at 8:24pm.

r = 16 cos3Q

Please explain. I do not know how to do this. Thank You!!

- Math -
**Damon**, Saturday, April 17, 2010 at 9:01pmif Q = pi/2 + h

r = 16 cos (3pi/2 +3h)

= 16[ cos 3pi/2 cos 3h - sin 3pi/2 sin h ]

cos 3pi/2 = 0

sin 3pi/2 = -1

so

16 sin h

is it the same for -h?

if Q = pi/2 - h

r = 16 cos (3 pi/2 -3h)

=16[ cos 3pi/2 cos 3h + sin3 pi/2 sin 3h

=16 (-sin h)

sin h is not the same as -sin h

so no, not symmetric about 3pi/2

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