Posted by **Anonymous** on Saturday, April 17, 2010 at 3:32pm.

Divide xy to 3rd power -3xy to 2nd power +2x to 2nd power y by xy

- elementary algebra -
**PsyDAG**, Sunday, April 18, 2010 at 10:43pm
Your description is unclear. If I have this right,

(xy^3 - 3xy^2 + 2x^2y)/xy = y^2 - 3y + 2x

However, from the way you have it stated, it could be:

([xy]^3 - [3xy]^2 + [2x]^2y)/xy = (xy)^2 - 9xy + 4x

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