Posted by rai on Saturday, April 17, 2010 at 5:32am.
8MB/image * 6 images = 48 MB total
48 MB * (1 second/2 MB) = 24 seconds
In part 2 the transmission is 100/2 or 50 times as fast
8MB/image * 6 images = 48 MB total
48 MB * (8 Mb/MB) * (1 second/2 Mb) = 192 seconds
In part 2 the transmission is 100/2 or 50 times as fast
This looks very much like the question I answered yesterday. That one had no part 2.
http://www.jiskha.com/display.cgi?id=1271466749
I agree with Damon's answer.
What is the answer to part two??
I mean in Scientific notation?
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