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May 22, 2015

Homework Help: Calculus (integrals)

Posted by Sarah on Friday, April 16, 2010 at 6:52pm.

Use the following formula for the sum of the cubes of the first integers to evaluate the limit in part (a).
1**3+2**3+...+n**3=((n(n+1))/2)**2

(a)lim n approaches infinity and the sum of n (top) and i=1 (bottom) with (3i/n)^3*(3/n)

I don't know how to solve this, can you help me out? Thank you.

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