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December 20, 2014

December 20, 2014

Posted by **Abbey** on Friday, April 16, 2010 at 2:58pm.

x = secQ

Y = tanQ

Would I use cos^2Q + sin^2Q = 1?

- Math -
**bobpursley**, Friday, April 16, 2010 at 3:06pmx^2+y^2= 1/cos^2 + sin^2/cos^2

=x^2( 1+sin^2)=x^2(2-cos^2)=

= x^2 (2-1/x^2)= 2x^2-1

or

y^2-x^2=-1

x^2-y^2=1

check all that

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