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Math

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Eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve.

x = secQ
Y = tanQ

Would I use cos^2Q + sin^2Q = 1?

  • Math - ,

    x^2+y^2= 1/cos^2 + sin^2/cos^2
    =x^2( 1+sin^2)=x^2(2-cos^2)=
    = x^2 (2-1/x^2)= 2x^2-1
    or
    y^2-x^2=-1
    x^2-y^2=1
    check all that

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