Posted by marco on Friday, April 16, 2010 at 12:26pm.
Factor Completely
2x^340x^2192x
I have a common factor of x so I rewrote the problem as
x(x^240x+192) then trying to use FOIL rewrote as
(x ) (x )
And that is where i'm stuck.

MathFactoring 2  marco, Friday, April 16, 2010 at 12:34pm
The last one shold be
(x ) (x )

MathFactoring 2  drwls, Friday, April 16, 2010 at 12:53pm
You factored out the 2x incorrectly. You should end up with 2x(x^220x+96).
The expression in parentheses can be factored into
(x12)(x8).
Now put it all together.

MathFactoring 2  marco, Friday, April 16, 2010 at 12:55pm
AAAAAAAAAAAAAAAHHHHHHH...thanks..it's in the details.
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