Posted by stacey graham on Friday, April 16, 2010 at 9:21am.
This seems to be more a "strength of materials" or civil/mechanical engineering design question than a physics problem.
Assume each rod gets half the load, or 6400 lb. Calculate the minimum circular area required to satisfy both the stress and the deflection requirements. From an available stock catalog for mild steel, pick the smallest diameter that satisfies both requirements.
I calculated reqd A got 32.8 psi to get diameter of 6.46 in/in. Am I going right way or did I miss something?
You missed something. 32.8 psi is hardly any stress at all.
Related Questions
physics - A stairwell is supported by two circular steel rods at one end. The ...
science - A stairwell is supported by two circular steel rods at one end. The ...
physics - A stairwell is supported by two circular steel rods at one end. The ...
physics - A stairwell is supported by two circular steel rods at one end. The ...
physics - A stairwell is supported by two circular steel rods at one end. The ...
physics - A .545kg ornament is hanging on a .75m uniform board, with mass .22kg ...
Applied physics - two men are carrying a 12m uniform ladder on their shoulders. ...
Physics - A uniform rigid pole of length L and mass M is to be supported from a ...
physics - A uniform rigid pole of length L and mass M is to be supported from a ...
physics - A uniform rigid pole of length L and mass M is to be supported from a ...
For Further Reading
