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October 31, 2014

October 31, 2014

Posted by **britt** on Friday, April 16, 2010 at 12:46am.

- physics -
**drwls**, Friday, April 16, 2010 at 7:06amYou need to know that the power in a vibrating string is

P = (1/2) ì ù^2 A^2 v .

Reference: http://hyperphysics.phy-astr.gsu.edu/hbase/waves/powstr.html

In that equation, ì (mu) is the mass per unit length, ù (omega) is the angular frequency of oscillation, A is the amplitude and v is the wave speed,

v = sqrt (T/ì). T is the tension.

With those equations, you can solve the problem yourself. Your value of mu (ì) is

ì = 0.0739 kg/m.

The wave speed is

v = sqrt(55.4/0.0739) = 27.4 m/s

Using the information provided about the power, solve for the angular frequency omega (ù). Divide that by 2 pi for the frequency in Hz.

- physics (P.S.) -
**drwls**, Friday, April 16, 2010 at 7:07amMy symbols for omega and mu did not come out in Greek like they should, but I hope you get the idea.

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