suppose 35 grams of waterare cooled from 15 c to 10 c how much heat is given off?
To calculate the amount of heat given off when water is cooled, you need to use the specific heat capacity of water and the formula for heat transfer.
The specific heat capacity of water is 4.184 J/g°C. This means that it takes 4.184 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
In this case, you have 35 grams of water that is being cooled from 15°C to 10°C. To calculate the heat given off, you need to find the temperature change and multiply it by the mass and specific heat capacity of water.
Temperature change = Final temperature - Initial temperature
= 10°C - 15°C
= -5°C
Note that we use a negative sign for the temperature change because the water is cooling.
Heat given off = Mass of water x Specific heat capacity x Temperature change
= 35 g x 4.184 J/g°C x -5°C
Now, you can do the calculation to find the amount of heat given off by the water.