Monday
April 21, 2014

Homework Help: Chemistry

Posted by Drew on Thursday, April 15, 2010 at 7:17pm.

When a sample of PCl5(g) (0.02087 mol/L) is placed in 83.00 L reaction vessel at 491.0 C and allowed to come to equilibrium the mixture contains 103.0 grams of PCl3(g). What is the equilibrium concentration (mol/L) of Cl2(g)?

PCl5(g) = PCl3(g)+Cl2(g)

Molar Mass
PCl5(g) 208.24
PCl3(g) 137.33
Cl2(g) 70.906

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