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September 30, 2014

September 30, 2014

Posted by **Abbey** on Thursday, April 15, 2010 at 4:42pm.

9x^2 + 4y^2 - 36x + 8y + 31 = 0

First I grouped the x and y's together.

9x^2 - 36x + ? + 4y^2 + 8y + ? = -31 + ? + ?

Then I factored the 9 and 4.

9(x^2-4x+4) + 4(x^2+2x+1) = -31+36+4

9(x-2)^2 + 4(x-1)^2 = 9

Then I divided it all by 9 and got:

(x-2)^2 / 1 + 4(x-1)^2 / 9 = 1

Is this correct or did I mess up somewhere?

- Math -
**Reiny**, Thursday, April 15, 2010 at 4:48pmlooks good

other than, you lost the y's, but I think that is just a typo.

- Math -
**Anonymous**, Wednesday, October 3, 2012 at 7:46amyou're wrong

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