Posted by brittany on Thursday, April 15, 2010 at 3:35pm.
The work done by the applied force is 95 x 5.2 = 494 J
Part of the work was done overcoming the friction force. The friction force is
Ff = 58*0.22*cos30 = 11.05 N and the work done against that force is 57.5 J
The work done increasing the gravitational potential energy is:
M*g*5.2*sin 30 = 150.8 J
That leaves a total of 494 - 57.5 - 150.8 J avaialbkle to increase kinetic energy
your awesome! but where did you get the 95 in the first equation?
95 N is the pulling force, which they tell you. That multiplied bhy the distance pulled is the work done by that force.
Thanks for the kind words; you'd better check my numbers anyway.
oh haha! sorry didnt see it
uhm where did you get 57.5? and what is M & g????
An 70.0 N box of clothes is pulled 24.0 m up a 30.0° ramp by a force of 115 N that points along the ramp. If the coefficient of kinetic friction between the box and ramp is 0.22, calculate the change in the box's kinetic energy.
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