geometry
in Triangle xyz, ab is a midsegment of xyz. ax is = 26, bz=36
ay is congruent to ax and bx is congruent ot bz.
I get that side yx = 52
and side yz is equal to 72
how do you get the value of side yz?
is it 72?
To determine the value of side YZ, we can use the fact that AB is a midsegment of triangle XYZ. A midsegment connects the midpoints of two sides of a triangle and is parallel to the third side.
Given that AB is the midsegment of triangle XYZ, we know that AB is parallel to side YZ and divides it into two congruent segments. Therefore, the length of YZ is twice the length of AB.
We are given that AX is 26 and BZ is 36. Since AB is the midsegment, we can conclude that AB = (AX + BZ)/2. Plugging in the values, we get AB = (26 + 36)/2 = 62/2 = 31.
So, AB = 31. Since YZ is twice the length of AB, YZ = 2 * 31 = 62.
Therefore, the correct value of side YZ is 62, not 72.