Posted by **Tiny** on Thursday, April 15, 2010 at 3:56am.

Suppose p and q are odd integers.

(a) Show that the quadratic equation x2 + px + q = 0 has no rational roots.

(A number á is a “root” of that equation if: á2 + pá + q = 0. A number is rational if it is expressible as

m/n for some integers m and n. )

(b) Does this result generalize to equations of the type xn + px + q = 0 ?

## Answer this Question

## Related Questions

- College Algebra--Still Confused - I have a few problems I need help with and ...
- math - Still looking at how to solve these... Both are cubic polynomials? 43x^3...
- College Algebra - I have a few problems I need help with and also do have ...
- Algebra2 - Find the polynomials roots to each of the following problems: #1) x^2...
- math - Still having problems solving this... 2x(2x + 1)^2 = 312 I started with: ...
- college math - I'm hoping I did thesse right. Solve each quadratic equation. (I ...
- amath - The roots of the quadratic equation x^2-mx+n=0 ,where m and n are ...
- algebra 2 - Factor completely with respect to the integers. 1. 9x^2 - 4 2. x^3...
- Math - I can't remember how you find the roots of quadratic equations other than...
- math - Factor: x^3 - 3/4x - 1/4 The answer is: (x - 1)(x + 1/2)^2 How do I learn...