Posted by **Mikhail** on Thursday, April 15, 2010 at 12:43am.

In 2000, NASA placed a satellite in orbit around an asteroid. Consider a spherical asteroid with a mass of 1.00×1016 and a radius of 8.50 .

What is the speed of a satellite orbiting 4.70km above the surface?

What is the escape speed from the asteroid?

- Physics -
**drwls**, Thursday, April 15, 2010 at 1:49am
You need to provide units for your quantities. I will have to assume your 8.50 is km and your 10^16 is kg.

4.70 km above the surface is R = 13.2 km (or 1.32*10^4 m) from the center

The orbital speed satisfies

G M/R^2 = V^2/R

where M is the asteroid mass and you know what G is. Solve for V.

V = sqrt(GM/R)

For the escape velocity Ve from the asteroid FROM THE SURFACE, where R' = 8.50 *10^3 m,

Ve^2/2 = GM/R'

Ve = sqrt(2 G M/R')

Note that a different radius, R', must be used.

## Answer this Question

## Related Questions

- Physics - In 2000, NASA placed a satellite in orbit around an asteroid. Consider...
- Phsyics - In 2000, NASA placed a satellite in orbit around an asteroid. Consider...
- physics - NASA launches a satellite into orbit at a height above the surface of...
- PHYSICS HELP - A satellite of mass m is orbiting the earth, mass M , in a ...
- Physics Classical Mechanics - A satellite of mass m is orbiting the earth, mass ...
- physics - Consider an asteroid with a radius of 15.5 km and a mass of 3.46E+15 ...
- physic - Between the orbits of Mars and Jupiter, several thousand small objects ...
- physics - The physics of satellite motion around Jupiter. A satellite of mass 2....
- Physics 141 - A satellite is in a circular orbit around an unknown planet. The ...
- Physics 141 - A satellite is in a circular orbit around an unknown planet. The ...

More Related Questions