Homework Help: chemistry

Posted by andy on Wednesday, April 14, 2010 at 11:51pm.

When CO(g) (38.11 grams) and 96.48 grams of Cl2(g) in a 140.0 L reaction vessel at 782.0 K are allowed to come to equilibrium the mixture contains 0.4080 mol of Cl2CO(g). What is the equilibrium concentration (mol/L) of CO(g)?
CO(g)+Cl2(g) = Cl2CO(g) Can anyone help with the steps to how to complete this problem?

chemistry - DrBob222, Thursday, April 15, 2010 at 12:15am
Set up an ICE chart.
moles CO = 38.11/molar mass CO = ??
moles COCl2 at equilibrium = 0.4080; therefore, COCl2 must have increased by 0.4080 mols while CO an CL2 decreased by 0.4080. How much does that leave for CO.
Initial moles - moles at equilibrium = moles remaining. That divided by 140 L = concn.

Answer this Question

Related Questions

Math - Maggie's surprise gift weighs between 8.48 grams and 11.25 grams. ...
CHEMISTRY - When NO(g) (0.06623 mol/L) and 422.6 grams of Cl2(g) in a 180.0 L ...
Chemistry - When a sample of PCl5(g) (0.02087 mol/L) is placed in 83.00 L ...
Chemistry - For the reaction shown, compute the theoretical yield of product (in...
Chemistry - For the reaction shown, compute the theoretical yield of product (in...
Chemistry - When 0.100 mol of carbon is burned in a close vessel with 8.00g of ...
Chemistry - When 0.100 mol of carbon is burned in a close vessel with 8.00g of ...
chemistry - Phosgene (COCl2) is an extremely poisonous gas that was used ...
Chemistry - In an industrial process, the following reaction is carried out in ...
chemistry - In an industrial process, the following reaction is carried out in ...

For Further Reading

First Name:
School Subject:
Answer: