posted by andy on .
When CS2(g) (545.0 grams) and 57.71 grams of H2(g) in a 200.0 L reaction vessel at 961.0 K are allowed to come to equilibrium the mixture contains 2.447 mol of CH4(g). What concentration (mol/L) of CS2(g) reacted?
CS2(g)+4H2(g) = CH4(g)+2H2S(g)
Look at the problem just up the board (COCl2). This is worked the same way.