Homework Help: chemistry

Posted by andy on Wednesday, April 14, 2010 at 11:41pm.

When CS2(g) (545.0 grams) and 57.71 grams of H2(g) in a 200.0 L reaction vessel at 961.0 K are allowed to come to equilibrium the mixture contains 2.447 mol of CH4(g). What concentration (mol/L) of CS2(g) reacted?

Molar Mass
CS2(g) 76.15
H2(g) 2.016
CH4(g) 16.043
H2S(g) 34.086

CS2(g)+4H2(g) = CH4(g)+2H2S(g)

chemistry - DrBob222, Thursday, April 15, 2010 at 12:18am
Look at the problem just up the board (COCl2). This is worked the same way.

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