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July 24, 2014

July 24, 2014

Posted by **zach** on Wednesday, April 14, 2010 at 10:35pm.

- math -
**Reiny**, Wednesday, April 14, 2010 at 10:56pmlet the value of the '45 nickel be $x

then the Jefferson nickel is worth (8/7)x

x + 8x/7 = 15

7x + 8x = 105

15x = 105

x = 7

take it from there.

- math -
**zach**, Wednesday, April 14, 2010 at 11:00pmThank you so much Reiny.

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