Posted by zach on Wednesday, April 14, 2010 at 10:35pm.
let the value of the '45 nickel be $x
then the Jefferson nickel is worth (8/7)x
x + 8x/7 = 15
7x + 8x = 105
15x = 105
x = 7
take it from there.
Thank you so much Reiny.
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