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December 25, 2014

December 25, 2014

Posted by **heather** on Wednesday, April 14, 2010 at 10:23pm.

9p^2+mn^2+9m+p^2n^2

- math -
**Reiny**, Wednesday, April 14, 2010 at 11:05pmFor grouping you usually have an even number of terms.

look at pairs of terms and see if the same common factor is found in "pairs"

9p^2+mn^2+9m+p^2n^2

=9p^2 + p^2n^2 + mn^2 + 9m

= p^2(9 + n^2) + m(n^2 + 9)

= (n^2 + 9)(p^2 + m)

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