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Posted by on Wednesday, April 14, 2010 at 5:27pm.

A compressed gas cylinder contains 1.00 103 g of argon gas. The pressure inside the cylinder is 2035 psi (pounds per square inch) at a temperature of 15°C. How much gas remains in the cylinder if the pressure is decreased to 610. psi at a temperature of 30.°C?

Thanks for the help in advance :)

  • chemistry - , Wednesday, April 14, 2010 at 5:46pm

    Do you mean that you open the valve on the cylinder and release Ar gas until the pressure is decreased to 610 psi at 30 C?

  • chemistry - , Wednesday, April 14, 2010 at 5:48pm

    ohh yes i think so

  • chemistry - , Wednesday, April 14, 2010 at 5:51pm

    I would go to google, type in "2035 psi to atmospheres" without the quotation marks. Do the same for 610 psi. Then use PV = nRT to calculate n remaining in the vessel and convert that to grams. Subtract from the initial amount to obtain the grams Ar remaining.

  • chemistry - , Wednesday, April 14, 2010 at 6:03pm

    i found both atmospheres
    2035=138.473537
    610=41.508038

    so it would be 1.00103(2035)=?

  • chemistry - , Wednesday, April 14, 2010 at 6:18pm

    I don't think so. You haven't used PV = nRT
    I would substitute P, V, R, and T (don't forget to change T t Kelvin) from the final conditions and calculate n, number of moles. Then moles = grams/molar mass and determine grams, then subtract from the initial grams to find that remaining.

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