Posted by kristen on Wednesday, April 14, 2010 at 5:27pm.
Do you mean that you open the valve on the cylinder and release Ar gas until the pressure is decreased to 610 psi at 30 C?
ohh yes i think so
I would go to google, type in "2035 psi to atmospheres" without the quotation marks. Do the same for 610 psi. Then use PV = nRT to calculate n remaining in the vessel and convert that to grams. Subtract from the initial amount to obtain the grams Ar remaining.
i found both atmospheres
2035=138.473537
610=41.508038
so it would be 1.00103(2035)=?
I don't think so. You haven't used PV = nRT
I would substitute P, V, R, and T (don't forget to change T t Kelvin) from the final conditions and calculate n, number of moles. Then moles = grams/molar mass and determine grams, then subtract from the initial grams to find that remaining.
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