college physics
posted by zidd on .
Interestingly, there have been several studies using cadavers to determine the moment of inertia of human body parts by letting them swing as a pendulum about a joint. In one study, the center of gravity of a 5.0 kg lower leg was found to be 18 cm from the knee. When pivoted at the knee and allowed to swing, the oscillation frequency was 1.6 Hz.What was the moment of inertia of the lower leg?
PLEASE WORK IT OUT, I HAVE TRIED DO IT, BUT AM NOT GETTING THE RIGHT ANSWER, PLEASE HELP
THANKS

period= 2PI sqrt (I/mg*.18)
I= mg*.18*Period^2/(2PI)^2
check that. Period= 1/1.6 sec