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December 19, 2014

December 19, 2014

Posted by **RAJESH** on Wednesday, April 14, 2010 at 6:51am.

countries, random samples yielded the following results :

n1 = 12O, X1 = 62.7 , S1 = 2.50

n2: 150, X2 : 61.8 , S2 = 2.62

where the measurements are in inches. Use 0.05 level of significance to test the difference between ti-re average heights.

- statistics -
**PsyDAG**, Wednesday, April 14, 2010 at 12:58pmFirst question: one-half = 50%

"X" is typically used to stand for a raw score. If you don't have the symbol, you can write out "mean."

Z = (μ1 - μ2)/Standard error of difference between means (SEμ-μ)

SEμ-μ = √(SEμ1^2 + SEμ2^2)

SEμ = SD/√(n-1)

You are looking for z > 1.96 to reject Ho at .05 level.

I'll let you do the calculations.

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