Use the relativistic coordinate transformation
(x, y, z, t) − (x′, y′, z′, t′) shown and given
below where the latter frame S′, (x′, y′, z′, t′),
has a velocity 2.69813 × 108 m/s in the
positive direction relative to the frame S,
(x, y, z, t).
For convenience, assume that the origins of the two reference frames overlap at time
t = t′ = 0.
what is the observed time interval T = t2 − t1 in the stationary reference frame given T′ = t′2 − t′1 in the moving reference frame?
The speed of light is 2.99792 × 108 m/s and the time measured in the primed frame is 52 s
there were some other details for this problem but the above is the question..what is the time interval...
so far i've got the speed of light, velocity, i found B= 0.900000667, Y=2.294164587, and t'=52 seconds
and now i'm stuck as to how to plug them in to find the answer. please help thanks
College Physics - Angie, Thursday, April 15, 2010 at 12:03am
so i figured it out....its simply the y* t' = answer