Posted by anonymous on .
Find the molecular mass of a solute by freezing point depression. Solvent: para-dichlorobenzene Freezing point of pure solvent: 53.02C Mass of unknown substance: 2.04g Freezingpointdepressin constant:7.1c/m Mass of para-dichlo...: 24.80g Freexing point solution: 50.78 C Can you explain how you got it, Please and thank you
ap chem -
delta T = Kf*molality.
molality = moles/kg solvent.
moles = grams/molar mass.
Calculate molar mass.
ap chem -
Temp of solvent - Temp of solution = constant x molality
solve for molality.
molality = mol of solute/kg of solvent
molality = change in Temp/constant
molality = (53.02-50.78)/7.1 = 0.3155 mol/kg
Convert to mol/g, so divide by 1000g.
molality = 3.155e-4 mol/g
multiply molality by grams of solvent to get moles of solute.
3.155e-4 mol/g x 24.8 g = 0.007824 mol
Now you have moles of solute. Solve for molecular mass by diving the grams of the solute by the calculated moles of solute.
Molecular mass of solute = 2.04 g/0.007824 mol = 260.73 mol/g of solute.