Posted by Trixie on Tuesday, April 13, 2010 at 10:54pm.
Nevermind...I realized that the problem I was using as an example called for 1 g of the reactant used....this didn't....so I have my correct answer now. Thanks!
Still stumped on my earlier question though...
I think I've answered that in an earlier response. I think you are looking at a neutron.
you have the right answer but dont factor in one gram of substance, it wants the amount per alpha decat there are alot of alpha decays in a gram.
So it is just 1.016E-12
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