# Physics

posted by
**Emily**
.

The work function for potassium is 2.24eV.

If potassium metal is illuminated with light of wavelength 310 nm,

find the maximum kinetic energy of the photoelectrons.

I have tried everything and still keep getting the wrong answer.

The speed of light is 3 × 108 and Planck’s constant is 6.62607 × 10−34

and the answer suppose to be in units of eV.

i used the equation MaxKE = h*c/ (wavelength x10^-9)

and then subtract (2.24 * 1.602x10^-19)

its not correct apparently, please help