Posted by Emily on Tuesday, April 13, 2010 at 10:09pm.
The work function for potassium is 2.24eV.
If potassium metal is illuminated with light of wavelength 310 nm,
find the maximum kinetic energy of the photoelectrons.
I have tried everything and still keep getting the wrong answer.
The speed of light is 3 × 108 and Planck’s constant is 6.62607 × 10−34
and the answer suppose to be in units of eV.
i used the equation MaxKE = h*c/ (wavelength x10^-9)
and then subtract (2.24 * 1.602x10^-19)
its not correct apparently, please help
Physics - Emily, Wednesday, April 14, 2010 at 2:05am
i figured it out after all - thanks
Physics - drwls, Wednesday, April 14, 2010 at 6:27am
Please include your units for physical quantities. Numbers are not enough.
Physics - gina, Wednesday, April 14, 2010 at 7:57pm
kmax = hf - e
kmax = h ( f becomes : c over lambda)- e
e = ( Evev * 1.6 *10exp -19)
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