posted by Emily on .
The work function for potassium is 2.24eV.
If potassium metal is illuminated with light of wavelength 310 nm,
find the maximum kinetic energy of the photoelectrons.
I have tried everything and still keep getting the wrong answer.
The speed of light is 3 × 108 and Planck’s constant is 6.62607 × 10−34
and the answer suppose to be in units of eV.
i used the equation MaxKE = h*c/ (wavelength x10^-9)
and then subtract (2.24 * 1.602x10^-19)
its not correct apparently, please help